6x^2+10x=4-10x-6x^

Solution for 6x^2+10x=4-10x-6x^ equation:

6x^2+10x=4-10x-6x^

We move all terms to the left:

6x^2+10x-(4-10x-6x^)=0

We get rid of parentheses

6x^2+10x+10x+6x^-4=0

We add all the numbers together, and all the variables

6x^2+26x-4=0

a = 6; b = 26; c = -4;
Δ = b2-4ac
Δ = 262-4·6·(-4)
Δ = 772
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{772}=\sqrt{4*193}=\sqrt{4}*\sqrt{193}=2\sqrt{193}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{193}}{2*6}=\frac{-26-2\sqrt{193}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{193}}{2*6}=\frac{-26+2\sqrt{193}}{12}
$